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Gottee guy Clawedfrogsrule Gottee guy Gottee guy Gottee guy DuckMonster Gottee guy Gottee guy Clawedfrogsrule DuckMonster 
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Gottee guy View Profile 
Can someone help me out? i have a math problem i cant find the awnser to!can someone help out?Farmer Joe has chickens and cows roaming in his field. When he counts them, he has 19 heads and 62 feet. How many cows and how many chickens does farmer brown have? remember chickens have 2 feet,cows 4 feet. 

08/26/08 06:45pm 


Clawedfrogsrule View Profile 
Message To: Gottee guy In reference to Message Id: 1843362 Can someone help me out? 12 cows and 7 chickens. I just drew 19 circles (one for each head) and then did two legs each to start, then added two more once I got through them all, once I got 62 legs I stopped and got my answer :) 

08/26/08 07:04pm 


Gottee guy View Profile 
Message To: Clawedfrogsrule In reference to Message Id: 1843378 Can someone help me out? nice,thanks! 

08/26/08 07:25pm 


Gottee guy View Profile 
Message To: Gottee guy In reference to Message Id: 1843404 Can someone help me out? are you sure not 6 chicks and 13 cows? 

08/26/08 07:28pm 


Gottee guy View Profile 
Message To: Gottee guy In reference to Message Id: 1843406 Can someone help me out? nevermind,thanks again! 

08/26/08 07:29pm 


DuckMonster View Profile 
Message To: Gottee guy In reference to Message Id: 1843407 Can someone help me out? Hey Gottee, the solution given by Clawed works. But it will not necessarily help you understand how to solve the problem.So, try to follow the logic and the algebra. you have a mixture of animals, their total number is 19. This is expressed as "X + Y = 19" The animals are different, in that some have 4 legs, some have two and the total number of legs adds up to 62. This is expressed as "4X + 2Y = 62" This can be simplified by dividing all by 2 into: "2X + Y = 31" So, now we see we have two e4quations that we can solve for "Y" "Y = 19  X" And, also "Y = 31  2X" So, since we have two equations equal to "Y", they are also equal to each other: "31  2X = 19  X" Subtract 19 from both sides: "12  2X = X" Add 2X to both sides: "12 = X" Time to find "Y" "X + Y = 19" "12 + Y = 19" "Y = 7" Time to check Answers: "4X + 2Y = 62" "4(12) + 2(7) = 62" "48 + 14 = 62 Answer Correct 

08/26/08 08:54pm 


Gottee guy View Profile 
Message To: DuckMonster In reference to Message Id: 1843553 Can someone help me out? yeah, someone else did it that way,but most of my class just did it clawed’s way. i get it though.i’ll use that formula if i have another problem like tat. 

08/27/08 03:33pm 


Gottee guy View Profile 
Message To: Gottee guy In reference to Message Id: 1844231 Can someone help me out? okay,another question,i think i know the awnser just not 100 pecent sure.how many WAYS can you make $1.00 by nickels,dimes,and quarters? no, by all means i do not want to figure it out the hard way just for one problem, so i thought can i divide 100 into 3 and get 33 ways as an awnser? would that be correct? 

08/27/08 03:37pm 


Clawedfrogsrule View Profile 
Message To: Gottee guy In reference to Message Id: 1844235 Can someone help me out? I think there are much more than that...I don’t remember the right way to do it though...ugh this one is going to bother me! lol 

08/27/08 05:36pm 


DuckMonster View Profile 
Message To: Gottee guy In reference to Message Id: 1844235 Can someone help me out? OK, I’ll take a shot at it. The question asks how many WAYS. This is the same as asking how many permutations. You do have to look at some basic combinations to be able to figure this out.I looked at 2 quarters. 2 quarters can be: 2Q 1Q, 2D, 1N 1Q, 1D, 3N 1Q, 5N 5D 4D, 2N 3D, 4N 2D, 6N 1D, 8N 10N This is 10 different combinations. So, we have 2 groups of 2 quarters, each having 10 possible combinations, how many permutations are there for combining those two groups. That is simply the multiplication of the number of those combinations. 10 X 10, or 100 possible ways to make a dollar. 

09/02/08 09:47am 
